Given that a to the power X = b to the power y = c to the power Z and b square = ac. Prove that 1 by X + 1 by Z = 2 by y
Please answer this in a picture or do the full maths process.. This is really urgent
Answers
Answered by
3
Hi ,
It is given that ,
a^x = b^y = c^z
Let a^x = b^y = c^z = k
1 ) a^x = k implies a = k^1/x
2 ) b^y = k implies b = k^1/y
3 ) c^z = k implies c = k^1/z
Now ,
b² = ac [ given ]
( k^1/y )² = ( k^1/x ) ( k^1/z )
k^2/y = k^( 1/x + 1/y )
[ Since i ) ( a^m )ⁿ = a^mn
ii ) a^m × a^n = a^ m+n ]
2/y = 1/x + 1/z
***************************
Since ,
If a^m = a^n then m = n
*****************************
Therefore ,
1/x + 1/z = 2/y
I hope this helps you.
: )
It is given that ,
a^x = b^y = c^z
Let a^x = b^y = c^z = k
1 ) a^x = k implies a = k^1/x
2 ) b^y = k implies b = k^1/y
3 ) c^z = k implies c = k^1/z
Now ,
b² = ac [ given ]
( k^1/y )² = ( k^1/x ) ( k^1/z )
k^2/y = k^( 1/x + 1/y )
[ Since i ) ( a^m )ⁿ = a^mn
ii ) a^m × a^n = a^ m+n ]
2/y = 1/x + 1/z
***************************
Since ,
If a^m = a^n then m = n
*****************************
Therefore ,
1/x + 1/z = 2/y
I hope this helps you.
: )
mysticd:
press red heart.
Similar questions