Question

Given that AB and AC are tangents to the
circle and AC = BC, then 2CAB in the given
figure is equal to​

Answer 1

Answer:

AB and AC are tangents

Therefore AB = AC

since AC = BC

therefore AB = BC = AC

therefore ABC is an equilateral triangle

therefore angle CAB = 60 degree

therefore 2CAB = 2×60 = 120 degree Ans

Answer 2

The angle CAB in the given figure is 45° when we have a AB and AC are tangents to the circle and AC=BC.

Given that,

In the picture we have a AB and AC are tangents to the circle and AC=BC

We have to find angle CAB in the given figure.

We know that,

In triangle ABC,

∠BCA=90°

Angle inscribed in semi-circle

AC=BC is given

∠ABC=∠CAB  

Opposite angles of equal sides are equal

∠CAB+∠ABC+∠BCA=180°

∠CAB+∠CAB+90° =180°

2∠CAB=180 °-90°

2∠CAB=90°

∠CAB=45°

Therefore, The angle CAB in the given figure is 45° when we have a AB and AC are tangents to the circle and AC=BC.

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