Given that ∆ ABC~ ∆ DEF & AB =2 cm,BC =3cm,DE = 4 cm ,EF = 6 cm.If DF = 8 cm,then AC = ? *
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Given that ∆ ABC~ ∆ DEF & AB =2 cm,BC =3cm,DE = 4 cm ,EF = 6 cm.If DF = 8 cm,then AC = ? *
AC is 4cm
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The length of AC is 4 cm.
Given:
∆ ABC~ ∆ DEF
AB=2 cm, BC=3cm, DE=4 cm, EF=6 cm, DF=8 cm
To find:
The length of AC
Solution:
The two given triangles are similar and so, the ratio of their sides that are corresponding will be equal.
Since ∆ ABC ~ ∆ DEF, AB/DE=BC/EF=AC/DF.
The ratio of the sides will remain equal.
Using the given lengths of the sides,
2/4=3/6=AC/8
1/2=1/2=AC/8
So, on equating AC/8 and 1/2, we get
AC/8=1/2
AC=1/2×8
AC=8/2
AC=4 cm
Therefore, the length of AC is 4 cm.
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