Given that ∆abc is a right-angled isosceles triangle with ∠ACB=90°. D is the mid-point of BC, CE is perpendicular to AD, intersecting AB and AD at e and f respectively. prove that ∠CDF =BDE
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If the isosceles right triangle ABC with AB is the hypotenuse, D is the midpoint of BC and CE is perpendicular to AD,
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