Question

Given that ∆ABC is an equilateral triangle of side 1cm , ∆BDC is iscoceles triangle with DB = DC outward of ∆ABC and angle BDC =120 . If points M and N are on AB and AC respectively such that angle MDN =60. find perimeter of ∆AMN .

Answer 1

1. Perimeter of D is opposite to A.
2. Perimeter of DB is equal to DC.
3. Angle BDC is equal to 120 degree.
4. If M and N are points on AB and AC, MDN is equal to 60 degree.

Use these steps and see the above attachment to solve the sum.

Hope it helps!!!