Question

Given that ACD is more than CDE and CDE is 22 more than DAC also the sum of
BCE and BDE Is 26 and EBF 80. Find the value of BEF​

Answer 1

Answer:

30°

Step-by-step explanation:

In ∆ACD,

∆ACD= ∆CDE+4°

∆CDE= ∆DCA+22°

=>∆ACD= 70°(Since, sum of all angles in a triangle is 180°)

∆CDE= 66°

∆DAC= 44° Let ∆BCE be a, then ∆BDE is 26-a (given)

Thus, in ∆CFD,

∆FCD+∆CDF+∆DFC= 180°

=> 70-a+66-26+a+∆DFC= 180°

∆DFC= 70°

∆BFE= 70° (Since, opposite angles are al)

v, in ∆BFE,

EBF+∆BFE+∆FEB=180°

80°+70°+x=180°

x= 30°

Hope It Helps You