Given that bacterium has generation time of 0.5 h, starting with an initial inoculum of 2 x 105 the count after 3 h
of culture will be
a) 3.2 x 106 b) 6.4 x 106 c) 12.8 x 106 d) 12.8 x 107
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0.5h = 2 x 105
after 3h = 0.5+0.5+0.5+0.5+0.5+0.5
=2x105+2x105+2x105+2x105+2x150+2x105
=1260
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