Given that, C(n,r):C(n,r+1)=1:2 and C(n,r+1):C(n,r+2)=2:3
What is n equals to?
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Step-by-step explanation:
We know that nCr = n!/r!.(n-r)!
nCr/nC(r+1) = 1/2 =>
{n!/r!.(n-r)!}/n!/{(r+1)!(n-r-1)! = 1/2
=> (r+1)/(n-r) = 1/2 => 2r+2 = n-r
=> 3r + 2 = n ……..(1). Also
nC(r+1)/nC(r+2) = 2/3
=>{n!/(r+1)!.(n-r-1)!}/{n!/(r+2)!.(n-r-2)!} = 2/3
=> (r+2)/(n-r-1)= 2/3
=>3r + 6 = 2n - 2r - 2 => 5r + 8 = 2n . Using (1) in this we get
5r+8 = 2(3r+2) => 5r+8 = 6r + 4 => r = 4 using this in (1) we get 3×4+2 = n => n = 14
So r= 4 and n = 14
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