Given that co efficienct of curvature 1.4,d30=3mm d10=.6mm based on this information of particles size distribution for use as subgrade ,then the co efficient of uniformity will be
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Given Given that co efficient of curvature 1.4, D 30 =3 mm D 10 =.6 mm based on this information of particles size distribution for use as sub grade ,then the co efficient of uniformity will be
- Given coefficient of curvature = 1.4
- D 10 = 0.6 mm
- D 30 = 3 mm
- So Coefficient of curvature = D 30^2 / D 60 x D 10
- 1.4 = 3^2 / D 60 x 0.6
- D 60 x 0.6 x 1.4 = 9
- D 60 = 9 / 0.84
- D 60 = 10.71 mm
- Coefficient of uniformity = D 60 / D 10
- = 10.71 / 0.6
- = 17.85
- Now since it is greater than 6 and coefficient of curvature lies between 1 and 3 it is well graded sand.
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