Given that cos 0 = ab where 0° < 0 < 90°, then find the value of cot 0.
Answers
Answered by
0
Answer:
cos 0 = ab
sin 0 = √( 1 - cos² 0 )
= √{ 1 - ( ab )² }
= √( 1 - a²b² )
cot o = cos o / sin o
= ab / √( 1 - a²b² )
Please mark me brainlist
Similar questions