given that cosα=1/2 and sinβ =1/2 then tan (α+β)=
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Step-by-step explanation:
Given θ is the arithmetic mean of α and β
⇒θ=
2
α+β
Also given cosα+cosβ=
2
3
⇒2cos(
2
α+β
)cos(
2
α−β
)=
2
3
⇒2cosθcos(
2
α−β
)=
2
3
.....(1)
sinα+sinβ=
2
1
⇒2sin(
2
α+β
)cos(
2
α−β
)=
2
1
⇒2sinθcos(
2
α−β
)=
2
1
.....(2)
Dividing (1) by (2), we get
cotθ=3
cosθ=
10
3
sinθ=
10
1
Now, sin2θ+cos2θ=2sinθcosθ+1−2sin
2
θ
=
10
6
+1−
10
2
=
5
7
(Since maximum value sin2θ+cos2θ is 2)
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