Given that cos(A-B) = cosAcosB + sinASinB. , Find the value of Cos15 .
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Heya......!!!!
If we want the value of cos15°....... , Then
Put A = 45° and B = 30°
We get
=>>> cos( 45° - 30° ) = cos45°cos30° + sin45°sin30°
=>>> cos15° = 1/√2 × √3/2 + 1/√2 × 1/2
♦Cos15° = (√3+1)/2√2 .
Hope it helps u ^_^
If we want the value of cos15°....... , Then
Put A = 45° and B = 30°
We get
=>>> cos( 45° - 30° ) = cos45°cos30° + sin45°sin30°
=>>> cos15° = 1/√2 × √3/2 + 1/√2 × 1/2
♦Cos15° = (√3+1)/2√2 .
Hope it helps u ^_^
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