Given that cos theta=1/2.find the value of 2 sec theta divided by 1+tan square theta
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cos theta=1/2
theta=60°
2sec theta/sec^2theta
=2/sectheta
2/2=1
theta=60°
2sec theta/sec^2theta
=2/sectheta
2/2=1
Answered by
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cos theta = 1/2
sec theta = 1/ cos theta = 1/ 1/2 = 2
sec^2 theta = 1 + tan^2theta
4 = 1 + tan^2 theta
required value : 2 sec theta / 1 + tan^2 theta
2*2 / 4 = 4 / 4 = 1
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