Question

given that cos0 = √3 upon 2 , then the value of cosec² 0 - sec² 0 upon cosec² 0 + sec² 0 is :​

Answer 1

Answer:

$cos = \sqrt{3 \div } 2$

$hupotenuse \: = 2$

$base \: = \sqrt{3}$

$perpendicular \: = 1$

${casec \: }^{2} = {(1 \div 2)}^{2}$

${casec}^{2} = 1 \div 4$

${sec }^{2} = { \sqrt{3 \div } 2}^{2}$

${sec \: }^{2} = 3 \div 4$

$according \: to \: question$

$\frac{1 - 3}{4} \div \frac{1 + 3}{4}$

$\frac{ - 2}{4} \times \frac{4}{4}$

$= \frac{ - 1}{2}$

Is the correct answer.