Given that cosec A + cot A = 1/4. Then,what is the value of cosec A - cot A?
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Answered by
1
Answer:
given cosecA + cotA= 1/4
cosecA = 1/4- cotA
thus,
putting value of cosecA
cosecA + cotA=1/4
1/4- cotA- cotA=1/4
1/4-2cotA=1/4
cotA= 0
therefore
cosecA=1/4
cosecA-cotA
1/4-cotA-cotA
= 1/4-0
1/4
Answered by
0
Answer:Given that
Cosec A+ cot A=1/4
Using identity
Cosec^2 =cot^2+1
So value of 1= cosec A ^2-cot A^2
Therefore
Cosec a square - cot square a= 1
Using identity
A square- b square =(a+b) (a-b)
So (cosec a - cot a) (cosec a+cot a) =1
(Cosec a- cot a) (1/4) =1
(Cosec a- cot a) =1×4
(Cosec A -cot A) =4
I hope it help you
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