Question

Given that cot theeta =7/8.Then evaluate (1+sin theeta)(1-sin theeta)/(1+cos theeta)(1-cos theeta)

Answer 1

Answer:

Hi friend,

given is cotθ=7/8 ⇒ opposite side = 8 and adjacent side=7 so, hypotenuse will be squareroot of sum of sqaures of 7 and 8 i.e sqrt7^2+8^2=√113 so now sinθ=8/√113 and cosθ=7/√113

(1+sinθ)(1-sinθ)/(1+cotθ)(1-cosθ)=1-sin^2θ/1+cotθ(1-cosθ)

                                                       = 1-64/113/1+7/8(1-7/√113)

on solving we get                        

49/(√113-7)√113