Question

Given that cotA=(12/5) and A is an acute angle, find cosA and sinA.j​

Answer 1

Step-by-step explanation:

Here, ABC is right angled triangle

∠A is an acute angle and ∠C=90

0

tan A = 5/12

BC/AC =5/12

Let BC = 5x and AC = 12x

From right angled ΔABC

By Pythagoras theorem, we get

AB

2

=(5x)

2

+(12x)

2

AB

2

=25x

2

+144x

2

AB

2

=169x

2

(i) cos A = Base/ Hypotenuse

= AC / AB

= 12x/13x

=12/13

(ii) cosec A = Hypotenuse/perpendicular

= AC / BC

= 13x /5x

= 13/5

cot A = Base/perpendicular

=12/5