given that DAV is a straight line find the value of the unknown
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in triangle CDA by angle sum property of a triangle 50+90+b=180 b=180-140=40 degrees b=40 degrees similarly in triangle CAB 35+90+c=180 c=180-125=55 degrees. Hope it helps please mark my answer the brainliest and follow me.
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in triangle DAC
angle D=50 degree
angle CAD =90 degree
angle DCA=b
angle D+angle CAD + angle DCA=180
50+90+b=180
140+b=180
b=40 degree
similarly, in triangle ABC
35+90+c=180
125+c=180
c=55 degree
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