Given that E and Fare events such that
P (E) = 0.6, P (F) = 0.3 and P(E∩F) = 0.2
find P(E|F) and P (F|E).
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Answer:
Correct option is
A
0.33
It is given that P(E)=0.6,P(F)=0.3 and P(E∩F)=0.2
⇒P(E∣F)=P(F)P(E∩F)=0.30.2=32
⇒P(F∣E)=P(E)P(E∩F)=0.60.2=31=0.33
Explanation:
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