Question

Given that f prime (t) = 8cos t + sec^2(t), -pi/2 less than t less than pi/2, and f(pi/3) = 2. Find f.

Answer 1

ln t]T x. = ln T - lim x→0+ ln x = с. Section 1.4. 2 For f(t) = t we get that a0 = 1. T T .... We see that all three Fourier series converge slowly. ..... S=sin(2*pi*440*t)+0.3*sin(2*pi ...

Answer 2

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Given that f prime (t) = 8cos t + sec^2(t), -pi/2 less than t less than pi/2, and f(pi/3) = 2

▶️2 xy

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