Question

Given that f(x)=2x−3, find the value of f−1(7).

Answer 1

Answer:

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Answer 2

Correct question is "Given that f(x)=2x−3, find the value of ${f(x)}^{ - 1} (7)$."

Answer:

Required value of ${f(x)}^{ - 1} (7)$ is 5.

Step-by-step explanation:

Given that f(x)=2x−3.

We want to find value of ${f(x)}^{ - 1} (7)$

To find the inverse of a function f(x), we can replace f(x) with y and then solve for x in terms of y. Then we interchange the x and y to get the inverse function ${f(x)}^{ - 1} (y)$ in terms of x.

So, starting with the function f(x) = 2x - 3, we replace f(x) with y:

y = 2x - 3

Next, we solve for x in terms of y:

y + 3 = 2x

x = (y + 3) / 2

Now we interchange x and y to get the inverse function ${f(x)}^{ - 1} (y)$ in terms of x:

${f(x)}^{ - 1} (7) = \frac{x + 3}{2}$

We want to find the value of ${f(x)}^{ - 1} (7)$

, so we plug in y = 7:

${f(x)}^{ - 1} (7) = \frac{x + 3}{2} \\ = \frac{7 + 3}{2} \\ \frac{10}{2} \\ = 5$

Therefore, the value of

${f(x)}^{ - 1} (7)$ is 5.

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