Given that f (x)= 4x-1, k (x)= 3x +7 and h(x)= 3x-1 ÷ x+5. What is Kf(2)
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∴ kf(2)
= k( f(2) )
= k(4 * 2 - 1)
= k(8 - 1)
= k(7)
= 3 * 7 + 7
= 21 + 7
= 28
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