given that for two vectors A and B |A×B| = |A.B| . find the acute angle between A and B .
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Answered by
1
In the above equation,by substuting formula for scalar and vector product,we get
cos x=sin x.
This is only possible for x=45°.
cos x=sin x.
This is only possible for x=45°.
Answered by
0
A*B = |A|*|B|sin x = |A|*|B|cos x
simplifying
tan x = 1.
hence
x= 45 deg.
simplifying
tan x = 1.
hence
x= 45 deg.
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