Given that HCF (2530,4400) = 11, LCM (2530,4400) = 253 x K. Then the value of K.
Answers
Answered by
6
Heya !!
Given that,
HCF (2530,4400) = 11, LCM (2530,4400) = 253 x K
As we know,
HCF × LCM = Product of two numbers
Now, HCF (2530, 4400) × LCM (2530, 4400) = 2530 × 4400
=> 11 × ( 253 × K ) = 2530 × 4400
=> K = ( 2530 × 4400 ) / ( 253 × 11 )
=> K = 10 × 400
=> K = 4000
Given that,
HCF (2530,4400) = 11, LCM (2530,4400) = 253 x K
As we know,
HCF × LCM = Product of two numbers
Now, HCF (2530, 4400) × LCM (2530, 4400) = 2530 × 4400
=> 11 × ( 253 × K ) = 2530 × 4400
=> K = ( 2530 × 4400 ) / ( 253 × 11 )
=> K = 10 × 400
=> K = 4000
Answered by
3
using formula
product of no. =lcm×hcf
2530×4400=253×k×11
k= 2530×4400/ 253×11
k= 11,132,000/2,783
k=4000
HOPE IT HELPS YOU '_'
product of no. =lcm×hcf
2530×4400=253×k×11
k= 2530×4400/ 253×11
k= 11,132,000/2,783
k=4000
HOPE IT HELPS YOU '_'
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