Question

Given that HCF (306, 1314)= 18. Find the LCM(306, 1314)
(Class 10 Maths Sample Question Paper)

Answer 1

SOLUTION:
Given:

First number= 306

Second number = 1314

HCF of two numbers(306,1314) = 18

Let x= 306, y= 1314

First number× second number= LCM(x,y) × HCF(x,y)

x × y = LCM(x,y) × HCF(x,y)

306 × 1314 = LCM × 18

LCM (x,y)= (306 × 1314) /18

LCM (x,y)= 17 ×1314

LCM(x,y) = 22,338

Hence , the LCM(306,1314)= 22,338

HOPE THIS WILL HELP YOU...

Answer 2

Heya friend,

Here is your answer,

Given : a = 306, b = 1314, HCF = 18
To find LCM,
Since,
LCM × HCF = a × b
Therefore,
=> LCM = (306 × 1314)/18
=> LCM = 402084/18
=> LCM = 22338. (ans)


Hope it helps you.
Thank you.