Math, asked by raoarjun694, 9 months ago

given that HCF (306, 657)=4 find LCM (306, 657)

Answers

Answered by Anonymous
3

As we know the product of HCF and LCM of two numbers is equal to the product of the two numbers we have

HCF (306, 657) x LCM (306, 657) = 306 x 657

\\ LCM (306, 657) = \frac{306\times 657}{HCF (306, 657) }\\ LCM (306, 657) = \frac{306\times 657}{9}\\ LCM (306, 657) =22338

so, the lcm is  22338.

Answered by Anonymous
1

Answer:

As we know the product of HCF and

LCM of two numbers is equal to the

product of the two numbers we have

HCF(A,B) × LCM(A,B) = A × B

HCF (306, 657) x LCM (306, 657) = 306 x 657

\\ LCM (306, 657) = \frac{306\times 657}{HCF (306, 657) }\\ LCM (306, 657) = \frac{306\times 657}{9}\\ LCM (306, 657) =22338

so, the

LCM :  22338

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