Question

Given that HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the

other.

Answer 1

suppose the two numbers are 'a' and 'b'
and a=161

a*b=HCF(a,b)*LCM(a,b)
161*b=23*1449
b=33347÷161
b=207

therefore your answer is 207

Answer 2

required no = (HCF×LCM)/161
= (23×1449)/161
= 23×9
= 207