given that in h atom the transition energy for n=1 to n=2 rydberg state is 10.2ev the energ for same transition on be+3 is
Answers
Answered by
2
Given that in the H- atom, the transition energy for n = 1 to n = 2 Rydberg states is 10.2eV, The energy for the same transition in Be3+Be3+ is :
A
20.4 eV
B
163.2 eV
C
30.6 eV
D
40.8 eV
Solution
E2=−13.6×164;E1=−13.6×16=−217.6E2=−13.6×164;E1=−13.6×16=−217.6
=−13.6×4=−64.4=−13.6×4=−64.4
E2−E1=−64.4+217.6=163.2
A
20.4 eV
B
163.2 eV
C
30.6 eV
D
40.8 eV
Solution
E2=−13.6×164;E1=−13.6×16=−217.6E2=−13.6×164;E1=−13.6×16=−217.6
=−13.6×4=−64.4=−13.6×4=−64.4
E2−E1=−64.4+217.6=163.2
Similar questions