Given that Kw for water is 10-13 M2 at 62°C,
compute the sum of poH and pH for a neutral
aqueous solution at 62°C ?
Answers
Answered by
0
Answer:
As we know,
K
w
=[H
+
][OH
−
];pH+pOH=−logK
w
=13.
Answered by
1
Answer:
hope the above pic. will help you ✨
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