Question

Given that l.c.m (320,120) = 960.find
H.c.f (320,120)

Answer 1

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✒ Given that l.c.m (320,120) = 960. Find H.c.f (320,120) .

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▶ The H.C.F of (320,120) is 40 .

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↗A×B = LCM(A,B) × HCF(A,B)

↗320×120 = 960×HCF(320,120)

↗HCF (320,120) = $\dfrac{320 \times 120}{960}$

↗HCF (320,120) = $\cancel{\dfrac{38400}{960}}$

➡ HCF(320,120) = 40

Additional information :-

• The product of the two numbers is equal to the product of their LCM and HCF.

• LCM is known as the least common multiple means the smallest number which is multiple to the given numbers.

• HCF is the highest common factor means that the largest number which is divisible by the given numbers.

☑ A×B = LCM{A,B} × HCF{A,B}

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Answer 2

Given :-

• 2 numbers are 320 , 120
• LCM of the numbers is 960

To Find :-

• HCF of the numbers = ??

Explanation :-

☆product of numbers is equal to the product of HCF and LCM .

➪Product of no. = HCF x LCM

➪320 x 120 = HCF x 960

➪HCF = $\sf\dfrac{320\times 120}{960}$

➪HCF = $\sf\dfrac{120}{3}$

➪HCF = 40

☆ Therefore HCF of 320 and 120 is 40 .

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Extra Information :-

• LCM is the lowest common factor . smallest no. by which both the digits can be divided

• HCF is the higgest common factor . Highest no. by which both the digits can be divided