Question

Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.​

Answer 1

$\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$

We know that according to the quotient law we can write log (10x/y2) as

log 10x – log y2

Now applying the law of product & power we get

log 10 + log x – 2 log y

We know that value of log 10 = 1.

Putting its value we get, 1 + (m+n) – 2(m-n) = 1 - m + 3n (Ans)

Answer 2

Answer:

Step-by-step explanation: Given that log m =x+y

And log n = x-y

Log m^2 n= log m^2 + log n

2 log m +log n

2(x+y) + (x-y) =2x +2y +x-y

= 3x +y