given that log m = x + y and log n = x- y , express the value of log m 2 n in term of x and y
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Answer:
Given :
log m = x+y
log n= x−y
log m^2n
Let us simplify the given expression,
log m^2n=logm^2 + logn
=2log m + log n
By substituting the given values, we get
=2(x+y)+(x−y)
=2x+2y+x−y
=3x+y
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