Question

given that log x=m+n and log y=m-n,express the value of log (10x/y²) in terms of m and n .​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

ANSWER:10(m +  n) ÷ log(m - n)

Step-by-step explanation:

log x=m + n

dividing both sides by 'log' to get a value for 'x'

 x = log^-1 m + n #1

log y=m - n

dividing both sides by 'log' to get a value for 'y'

y= log^-1 m - n #2

 ∴ log (10x/y²)= log* (10(log^-1 m + n)÷(log^-1 m - n)^2)

since 'log^-1' is common to both numerator and denominator, you factorize

 log*log^-1(10(m + n)÷log( m - n))

 log* (1÷log)(10(m + n)÷log( m - n))

 At this point, log will eliminate log

∴Finale answer is;

                                   10(m +  n) ÷ log(m - n)