Question

Given that log10 2 = x and log10 3 = y, the value of log..60 is expressed as
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Answer 1

log (base 10) 2 = x

log(base 10) 3 = y

log(base 10) 60 = log(base 10) ( 2 x 3 x 10)

= log(base 10) 2 + log(base 10) 3 + log(base 10) 10

= x + y + 1

Answer 2

The correct answer is 1 + x + y.

Given: $log_{10} 2=x,log_{10} 3=y$.

To Find: Express $log_{10} 60$  in terms of x and y.

Solution:

$log_{10} 60$

= $log_{10} (10*2*3)$

= $log_{10}10+ log_{10}2+log_{10}3$

= 1 + $log_{10}2+log_{10}3$

= 1 + x + y

Hence, $log_{10} 60$ can be expressed as 1 + x + y.

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