Question

given that m+2,where m is a positive integers,is a zero of the polynomial q(x)=x²-mx-6.​

Answer 1

Answer:

The value of m is 1

Step-by-step explanation:

Factor theorem :

Let p(x) be a polynomial of degree greater than 1 and (x-a) is another linear polynomial , if p(x)=0 then (x-a) is a factor.

Answer 2

GIVEN :-

m+2 is a zero of polynomial ,

Q(x) = x^2 - mx - 6

TO FIND :-

Value of m

SOLUTION:-

==> x^2 - mx - 6 = 0   .................................(1)

Put the zero of the polymomial in equation (1),

==> (m+2)^2 - m(m+2) - 6 = 0

==>  m^2 + 4 + 4m - m^2 -2m - 6 = 0

==>  2m - 2 = 0

==> m = 2/2

==> m = 1

So, the value of m is 1