Question

Given that – mass of empty relative density bottle = 20 g

mass of empty relative density bottle + distilled water = 80 g

mass of empty relative density bottle + unknown liquid = 60 g

a. Determine the relative density of the liquid.

b. Will this liquid float over in water? Yes or no? Give reason also.​

Answer 1

Answer:

Density of water = 1 g cm³

(a) Volume of density bottle

Mass of empty density bottle = M1 = 21.8g

Mass of bottle + water = M2 = 41.8g

So, mass of water completely filling the density bottle = M2-M1

= 41.8 - 21.8 = 20g

1g of water has volume =cc

So, Volume of bottle = volume of water = 20cc = 20ml

(b) The relative density of liquid

Mass of 20 cc of liquid

= (mass of density bottle + mass of 20cc of liquid) - mass of density bottle

= 40.6 - 21.8

= 18.8 g

Mass of 20 cc of water = 20g

Relative density of liquid

$R.D = \frac{Mass\ of\ 20\ cc\ of\ liquid}{Mass\ of\ 20\ cc\ of\ water}=\frac{18.8}{20}=0.94$

Mass of 20 cc of water

Mass of 20 cc of liquid