Question

Given that n() = 40, n(A) = 25, n(B) = 15
and n(ANB) = 12.
Find: De Morgan laws
a. n(AUB)
c. n(B')
b. n(A)
d. n(ANB)​

Answer 1

Step-by-step explanation:

1. n(AUB)=n(A)+n(B)-n(ANB)
2. =25+15+12=52

1. n(B')=n()-n(B)
2. =40-15=25

1. n(A')=n(B)=15

1. n(ANB')=40-12=28