Given that one number is 7 times the other & that the difference is 75.
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Step-by-step explanation:
x+y = 56
x = 3y
Substitute for x in the first equation:
x + y = 56
x = 3y
3y + y = 56
Combine like terms:
4y = 56
Divide both sides by 4:
y = 14
So if y = 14, and x = 3y, then x = 42.
Now substitute for both x and y in both of the original equations to prove they are the correct values.
x + y = 56
x = 42
y = 4
42 + 14 = 56
56 = 56
x = 3y
x = 42
y = 14
42 = 3*14
42 = 42
So the two numbers, x and y, are 42 and
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