Question

Given that one of the roots of the equation :3x²+Px+1=0 is the square of the reciprocal of the other.The value of P is? ​

Answer 1

Answer:

-28/3

Step-by-step explanation:

Sum of roots=a+b=-P/3........(1)

product of root=a.b=1/3............(2)

given. a=(1/b)^2

Put value of a in (2)

1/b=1/3

b=3

put value of b in (2)

a=1/9

from (1)

1/9+3=-P/3

P=-28/3