Question

Given that P=(x^2-y^2)/(x^2+xy)
1. Express p in it's simplest form
2. Find the value of p if x=-4 and y=-6

Answer 1

HOPE IT HELPS YOU

Answer:

a ) x square - y square / x square + xy

(x + y ) ( x - y ) / x ( x + 1 ( because a square - b square = ( a + b ) ( a - b ) )

( x is common )

x - y /x

Therefore P = x - y /x

b ) x - y /x

b ) x - y /xPut the value of x = -4

b ) x - y /xPut the value of x = -4y = -6

b ) x - y /xPut the value of x = -4y = -6( -4 ) - ( - 6 )

b ) x - y /xPut the value of x = -4y = -6( -4 ) - ( - 6 )-4 + 6

b ) x - y /xPut the value of x = -4y = -6( -4 ) - ( - 6 )-4 + 62

b ) x - y /xPut the value of x = -4y = -6( -4 ) - ( - 6 )-4 + 62Therefore , the value of P is 2