Question

Given that P=x^2-y^2/x^2+xy.
1. express p in its simplest form
2. find the value of p if x=-4 and y=-6.​

Answer 1

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Answer:

a ) x square - y square / x square + xy

(x + y ) ( x - y ) / x ( x + 1 )

( because a square - b square = ( a + b ) ( a - b ) )

( x is common )

x - y /x

Therefore P = x - y /x

b ) x - y /x

Put the value of x = -4

y = -6

( -4 ) - ( - 6 )

-4 + 6

2

Therefore , the value of P is 2