Question

Given that points (3,2), Q(0,-4) and R(-3,x ) are collinear find x​

Answer 1

Answer:

P(3,2),Q(0,-4),R(-3,x)

area of triangle=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

                         0=1/2|3(-4-x)+0(x-2)-3(2+4)|

                          0=1/2|-12-3x+0-6-12|

                          0 =-24-3x-6

                          0=-3x-30

                            -3x=30

                                x=-30/3

                                   x=-10

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

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