Question

Given that radius of earth as 6400 km and acceleration due to gravity g=9.8 m/s^2.

Calculate the value of acceleration due to gravity at a altitude h=10 km and g at a depth d=10 km

Please solve​

Answer 1

g at height 10km :

g'= g(1-(2h/R))

$g {}^{h} = g(1 - (2 \times 10) \div 6400)$

which gives :

$g {}^{h} = 9.76$

g at a depth:

g'= g(1-d/r)

$g {}^{d} = (1 - 10 \div 6400)$

which gives g= 9.78