Given that root 2 is irrational, prove the (5+3 root 2) is an irrational numbers
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Given : √2 is irrational
Let (5+3√2) be a rational number
(5+3√2) = p/q where p,q are integers and q isn't equal to 0
3√2=(p-5q)/q
√2 = (p-5q)/3q
p, q are integers, so (p-5q)/3q is a rational number
As LHS= RHS, √2 becomes rational
This contradicts the fact that √2 is irrational.(given)
This contradiction arose because of our wrong assumption.
Therefore, (5+3√2) is irrational
Hope it helps!
Given : √2 is irrational
Let (5+3√2) be a rational number
(5+3√2) = p/q where p,q are integers and q isn't equal to 0
3√2=(p-5q)/q
√2 = (p-5q)/3q
p, q are integers, so (p-5q)/3q is a rational number
As LHS= RHS, √2 becomes rational
This contradicts the fact that √2 is irrational.(given)
This contradiction arose because of our wrong assumption.
Therefore, (5+3√2) is irrational
Hope it helps!
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