Question

Given that root 3 equal to 1.732 find the altitude of an equilateral triangle whose one side measure 6 CM​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Draw altitude of triangle ABC

Mark the point intersecting line BC as D

The triangle ADB will be a right angled triangle as the altitude in equilateral triangle are perpendicular bisector to base

AD^2+BD^2=AB^2

BD=3(AD bisects AB and 6/2=3)

AD^2 +9=36

AD^2=27

27=3×3×3

AD=√3×3×3=3√3=3×1.732

The altitude AD=5.196cm