Question

given that root 3 is a zero of the polynomial x cube + x square - 3 x minus 3 find its other two zeros

Answer 1

Hello,

If p(a) =0 ; then by factor theorem we can say that (x-a) is a factor of p(x)
Similarly, above root 3 is given
So, (x-root3) should be a factor of p(x)

Now, please refer to the photo for the used process.

Now, explanation of part 1 from attachment :
In the second step of division we got a term as follows :
-3x
-(1+ root3) root3 x

So, down (-) changes to (+)
So, it becomes

-3x
+(1+root3)root3 x

In down number, (1 + root3) root3 x can be written as (root3 + 3)x

We multiplied the outside root3

Now the division becomes :

-3x
+(root3 + 3)x

Now , taking x common we get the answer as

(-3+root3 + 3)x= root3 x

after this the normal division process. Please refer the above photograph for the used process...

Hope this will be helping you ✌️

Answer 2

Answer:

-root 3 and - 1

Step-by-step explanation:

Hope that helps you

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