Question

Given that saccharin has a molar mass of 183.18 g/mol, how many saccharin molecules are in a 40.0-mg (0.0400-g) sample of saccharin? How many carbon atoms are in the same sample? The molecular formula of saccharin C7H5NO3S.
PLS ANSWER MY Q

Answer 1

Answer:

sorry I do not know there answer

Answer 2

Answer:

9.17×10²⁰ C atoms

Explanation:

40.0 mg × 1g/1000mg=0.04g

0.04g C7H5NO3S × 1molecules/183.18g C7H5NO3S × 6.02×10²³/1mol = 1.31 × 10²⁰

1.31×10²⁰ C7H5NO3S molecules

1.31×10²⁰ C7H5NO3S molecules×7 C atoms/1molecule C7H5NO3S

=9.17×10²⁰ Carbon Atoms (C atoms)