Question

Given that sin 0=a/b, then tan 0=

Answer 1

Answer:

tan0 = a/(✓b^2 - a^2)

Step-by-step explanation:

sin0 = a/b

=> cos0 = ✓1 - sin^2 0

=> cos0 = ✓1-(a/b)^2

=> cos0 = (✓b^2 - a^2) / b

=> tan0 = sin0/cos0 = a/b / (✓b^2 - a^2) / b

=> tan0 = a/(✓b^2 - a^2)

Note: ^2 refers to square

✓ refers to square root