Question

Given that sin θ + 2 cos θ = 1, then prove that 2sinθ - cos θ = 2​

Answer 1

Answer:

thitha=90

2sin90-cos90=2(1) -0=2

Answer 2

HELLO DEAR,

GIVEN:- sin∅ + 2cos∅ = 1

now, on squaring both side

we get,

sin²∅ + 4cos²∅ + 4sin∅cos∅ = 1

=> (1 - cos²∅) + 4(1 - sin²∅) + 4sin∅cos∅ = 1

=> 1 + 4 - cos²∅ - 4sin²∅ + 4sin∅cos∅ = 1

=> 5 - cos²∅ - 4sin²∅ + 4sin∅cos∅ = 1

=> 4sin²∅ + cos²∅ - 4sin∅cos∅ = 4

=> (2sin∅ - cos∅)² = (2)²

taking square root both side,

=> 2sin∅ - cos∅ = 2

I HOPE IT'S HELP YOU DEAR,

THANKS