Question

given that sin a = √3/2 and cos b = 0 then the value of B - A is​

Answer 1

sin A=√3/2

A=60°

cosB=0

B=90°

Therefore :- B-A = 90°-60° = 30°

Answer 2

The correct answer is 30°.

Given: Sin A = $\frac{\sqrt{3} }{2}$ and cos B = 0.

To Find: B-A.

Solution:

Sin A = $\frac{\sqrt{3} }{2}$

A = 60°.

Cos B = 0

B = 90°

B - A = 90° - 60°

B - A = 30°

Hence, the Difference of B and A is 30°.

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